7+2+6+3+5+2
Is it divisible by 3 and 6?

Open in App

Solution

7+2+6+3+5+2 = 25
25 is neither divisible by 3, nor by 6.
A number is divisible by 3 only when the sum of the digits is divisible by 3.
A number is divisible by 6 if it is divisible by 2 and 3 both.
25 satisfies neither of the condition.

Suggest Corrections

Similar questions

Q. The number of divisors of

N = 2^{7} . 3^{3} . 5^{4}

divisible by 6 but not by 15 is

Q. Number of divisors of

2^{5} 3^{2} {.5}^{3}

which are divisible by

2

but not divisible by

6

and

8,

Q. A number lying between

1000

and

2000

is such that on division by

2, 3, 4, 5, 6, 7

and

8

leaves remainders

1, 2, 3, 4, 5, 6 a n d 7

respectively. The number is

Question 6

Which of the following expressions show that rational numbers are associative under multiplication.
(a) $\frac{2}{3} \times (\frac{- 6}{7} \times \frac{3}{5}) = (\frac{2}{3} \times \frac{- 6}{7}) \times \frac{3}{5}$
(b) $\frac{2}{3} \times (\frac{- 6}{7} \times \frac{3}{5}) = \frac{2}{3} \times (\frac{3}{5} \times \frac{- 6}{7})$
(c) $\frac{2}{3} \times (\frac{- 6}{7} \times \frac{3}{5}) = (\frac{3}{5} \times \frac{2}{3}) \times \frac{- 6}{7}$
(d) $(\frac{2}{3} \times \frac{- 6}{7}) \times \frac{3}{5} = (\frac{- 6}{7} \times \frac{2}{3}) \times \frac{3}{5}$

Question 6

Join BYJU'S Learning Program

7+2+6+3+5+2 Is it divisible by 3 and 6?

7+2+6+3+5+2 = 25 25 is neither divisible by 3, nor by 6. A number is divisible by 3 only when the sum of the digits is divisible by 3. A number is divisible by 6 if it is divisible by 2 and 3 both. 25 satisfies neither of the condition.

7+2+6+3+5+2
Is it divisible by 3 and 6?

7+2+6+3+5+2 = 25
25 is neither divisible by 3, nor by 6.
A number is divisible by 3 only when the sum of the digits is divisible by 3.
A number is divisible by 6 if it is divisible by 2 and 3 both.
25 satisfies neither of the condition.