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Division of Negative Numbers

-7 / 3*12 / 5...

Question

-7/3*(12/5 -4/21)

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Solution

=(-7/3)×((12/5)-(4/21))
=(-7/3)×((12×21)-(4×5))÷(5×21)
=((-7/3)(252-20))/(105)
=(-7/3)(232)÷105
=(-7×232)÷(105×3)
=(-232)/(15×3)
=(-232/45)
=-5.15555556.

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Similar questions

Find:

(i) (ii) (iii)

(iv) (v) (vi)

Verify each of the following :

(i) $(\frac{5}{7} \times \frac{12}{13}) \times \frac{7}{18} = \frac{5}{7} \times (\frac{12}{13} \times \frac{7}{18})$
(ii) $\frac{- 13}{24} \times (\frac{- 12}{5} \times \frac{35}{36}) = (\frac{- 13}{24} \times \frac{- 12}{5}) \times \frac{35}{36}$
(iii) $(\frac{- 9}{5} \times \frac{- 10}{3}) \times \frac{21}{- 4} = \frac{- 9}{5} \times (\frac{- 10}{3} \times \frac{21}{- 4})$

Q. Choose or find odd number pair

(3 - 4), (4 - 7), (5 - 12), (20 - 21)

Fill in the blanks.

(i) $(\frac{- 3}{17}) + (\frac{- 12}{5}) = (\frac{- 12}{5}) + (. . . . .)$

(ii) $- 9 + \frac{- 21}{8} = (. . . . . .) + (- 9)$

(iii) $(\frac{- 8}{13} + \frac{3}{7}) + (\frac{- 13}{4}) = (. . . . . .) + [\frac{3}{7} + (\frac{- 13}{4})]$

(iv) $- 12 + (\frac{7}{12} + \frac{- 9}{11}) = (- 12 + \frac{7}{12}) + (. . . . .)$

(v) $\frac{19}{- 5} + (\frac{- 3}{11} + \frac{- 7}{8}) = {\frac{19}{- 5} + (. . . . .)} + \frac{- 7}{8}$

(vi) $\frac{- 16}{7} + . . . . . = . . . . . . + \frac{- 16}{7} = \frac{- 16}{7}$

Solve:

(a) (b)

(c) (d)

(e) (f)

(g) (h)

(i)

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