Question

$7-3\frac{5}{9}=$ $3\frac{x}{9}$. Find x.

Answer 1

We have,

$7-3\frac{5}{9}=3\frac{x}{9}$

$\Rightarrow \frac{7}{1}-\frac{32}{9}=\frac{27+x}{9}$

$\Rightarrow \frac{63-32}{9}=\frac{27+x}{9}\left[L.C.Mof1\&9=9\right]$

$\Rightarrow 63-32=27+x\left[cancle9bothsides\right]$

$\Rightarrow 31=27+x$

$\Rightarrow x=31-27$

$\therefore x=4$

Hence , the value of $x=4$