The correct option is A 49 a=7 r= 37 S_(∞)=a1 r=71+37 =7107=4910 S_(∞)=4910 . ...

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Permutation

7-3+97-2749+....

Question

$7 - 3 + \frac{9}{7} - \frac{27}{49} + . . . . \infty$ equals

49

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10

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4.9

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\frac{49}{4}

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Solution

The correct option is A $49$
$a = 7$
$r = - \frac{3}{7}$
$S_{(\infty)} = \frac{a}{1 - r} = \frac{7}{1 + \frac{3}{7}}$
$= \frac{7}{\frac{10}{7}} = \frac{49}{10}$
$S_{(\infty)} = \frac{49}{10}$ .

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Similar questions

The H.C.F. of 4 $\times$ 27 $\times$ 3125, 8 $\times$ 9 $\times$ 25 $\times$ 7 & 16 $\times$ 81 $\times$ 5 $\times$ 11 $\times$ 49 is ____.

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16 \times 81 \times 5 \times 11 \times 49

(2 x + 7) (2 x - 7)

2 x - 9 y = 9, 5 x + 2 y = 27

\frac{7^{- 3} \times 12^{- 3} \times 3^{- 4} \times 49}{6^{- 4} \times 7^{- 1} \times 2^{- 4}}

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