Given, 3( x−1 )≤2( x−3 ).
Solve for x,
3( x−1 )≤2( x−3 ) 3x−3≤2x−6 3x−2x≤−6+3 x≤−3
All the real numbers less than or equal to −3 are the solutions of inequality, as x is a real number.
Therefore, solution set is ( −∞,−3 ].