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Question

7.36 g of a mixture of KCl and KI was dissolved in H2O to prepare 1 litre solution. 25 ml of this required 8.45 ml of 0.2 N AgNO3.
What is the percentage of KI in the mixture?

A
57.28
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B
47.28
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C
5.72
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D
49.12
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Solution

The correct option is A 57.28
We have a mixture containing KI+KCl.
Gram equivalents of mixture = Gram equivalents of AgNO3.
Let, x g be the weight of KI.
Then, the weight of KCl will be (7.36x) g.

(x166+7.36x74.5)=8.45×0.2×401000

On solving, we get x=4.216 g.

Percentage of KI=57.28%

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