Explanation of correct option We have ( 7/5)^ 1=__By the law of exponent (a)^ 1=1/a[ ( 7/5)^ 1 = 1/ 7/5; = 5/7 ]Hence, corr ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Powers with Negative Exponents

-7/5-1=

Question

${(\frac{- 7}{5})}^{- 1} =__$

$\frac{5}{7}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$\frac{- 5}{7}$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

$\frac{7}{5}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$\frac{- 7}{5}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B
$\frac{- 5}{7}$

Explanation of correct option-
We have- ${(\frac{- 7}{5})}^{- 1} =__$
By the law of exponent- ${(a)}^{- 1} = \frac{1}{a}$
$\begin{array}{rcl} {(\frac{- 7}{5})}^{- 1} & = & \frac{1}{\frac{- 7}{5}} \\ = & \frac{- 5}{7} \end{array}$
Hence, correct option is B.

Suggest Corrections

Similar questions

Question 96

Solve the following:

Express as a power of a rational number with negative exponent.
$(a) {({(\frac{- 3}{2})}^{- 2})}^{- 3} (b) (2^{5} \div 2^{8}) \times 2^{- 7}$

{log}_{3} (2 x^{2} + 6 x - 5) > 1

x

\frac{x}{y}

{(\frac{3}{5})}^{- 4} \times {(\frac{15}{10})}^{- 4} = {(\frac{x}{y})}^{- 4}

f (x) = \frac{(x - 3) (x + 2) (x + 6)}{(x + 1) (x - 5)}

f (x)

0 < x < 1000

[\frac{x}{2}] + [\frac{x}{3}] + [\frac{x}{5}] = \frac{31}{30} x

[x]

x

x

Join BYJU'S Learning Program