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Question

7.5 litre of the particular gas at S.T.P. as weight 16 gram. What is the V.D. of gas?

A
23.89
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B
24
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C
2.398
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D
22
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Solution

The correct option is A 23.89

Given,

volume - 7.5 l

weight - 16 g

Molecular mass = vapour density×2

At STP,

one mole of gas = 22.4 l

so, number of moles in 7.5 l = 122.4×7.5=0.3348 mole

0.334 mole of gas has weight - 16 g

one mole - 160.3348=47.78 g

Here, we got molecular mass - 47.78 g

Vapour density = 47.782=23.89

Hence, option A is the correct answer.


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