Question

7. At room temperature, volume of gas enclosed in a cylinder at 1atm pressure, is 10L. What will be the volume of gas at 20atm pressure? Compare the density of above gas at two different pressures .

Answer 1

According to Boyle's Law:

P₁V₁ = P₂V₂
V₂ = $\frac{P_1{V}_1}{P_2}=\frac{1\times 10}{20}=0.5l$

Also,

$$\begin{gathered} P_1{V}_1=P_2{V}_2 \\ {P}_1\frac{M}{{\rho }_1}=P_2\frac{M}{{\rho }_2} \\ \frac{P_2}{{\rho }_1}=\frac{P_2}{{\rho }_2} \\ withincreaseinpressure,densityincreases. \end{gathered}$$