7 bags of wheat flour each marked 5 kg actually contained following weights of flour (in kg) 4.97, 5.05, 5.08, 4.98,5.03,5.07,5.00, what is the probability that any of the bags chosen at random contained more than 5 kg of flour?

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Solution

$\begin{matrix} N u m b e r o f t o t a l b a g s = 11 N u m b e r o f b a g s c o n t a i n i n g m o r e t h a n 5 k g o f f l o u r = 7 (5.05, 5.08, 5.03, 5.06, 5.08, 5.04, 5.07) P (b a g c h o s e n c o n t a i n s m o r e t h a n 5 k g o f f l o u r) = \frac{N u m b e r o f b a g s w i t h m o r e t h a n 5 k g o f f l o u r}{t o t a l n u m b e r o f b a g s} = \frac{4}{7} . \end{matrix}$

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5 k g

(

k g) :

4.97, 5.05, 5.08, 5.03, 5.00, 5.06, 5.08, 4.98, 5.04, 5.07, 5.00

Find the probability that any of these bags chosen at random contains more than $5 k g$ of flour.

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4.97, 5.05, 5.08, 5.03, 5.00, 5.06, 5.08, 4.98, 5.04, 5.07, 5.00

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5 k g

4.97 5.05 5.08 5.03 5.00 5.06 5.08 4.98 5.04 5.07 5.00

5 k g

Eleven bags of wheat flour, each marked 5 kg actually contained the following weights of flour (in kg):

4.97, 5.05, 5.08, 5.03, 5.00, 5.06, 5.08, 5.08, 4.98, 5.04, 5.07, 5.00,

Find the probability that any of these bags chosen at random more than 5 kg of flour.

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