734-7- Here- stands for-

The correct option is C 14 ⇒31/4=7+(3△ ) ⇒31/4 7=3△ ⇒31 28/4=3△ ⇒ 3△ =3/4 △ =3/4×1/3=1/4 [△ =1/4] ...

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Byju's Answer

Standard X

Mathematics

Area of a Triangle Given Its Vertices

734=7+++. Her...

Question

$7 \frac{3}{4} = 7 + (△ + △ + △)$ . Here, $△$ stands for:

3

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4

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\frac{1}{4}

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\frac{3}{4}

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Solution

The correct option is C $\frac{1}{4}$
$\Rightarrow \frac{31}{4} = 7 + (3 △)$
$\Rightarrow \frac{31}{4} - 7 = 3 △$ $\Rightarrow \frac{31 - 28}{4} = 3 △$
$\Rightarrow 3 △= \frac{3}{4}$
$△= \frac{3}{4} \times \frac{1}{3} = \frac{1}{4}$
$[△= \frac{1}{4}]$

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Question 22

Which of the following is an example of distributive property of multiplication over addition for rational numbers.
(a) $- \frac{1}{4} \times {\frac{2}{3} + (\frac{- 4}{7})} = [- \frac{1}{4} \times \frac{2}{3}] + [- \frac{1}{4} \times (\frac{- 4}{7})]$
(b) $- \frac{1}{4} \times {\frac{2}{3} + (\frac{- 4}{7})} = [\frac{1}{4} \times \frac{2}{3}] - (\frac{- 4}{7})$
(c) $- \frac{1}{4} \times {\frac{2}{3} + (\frac{- 4}{7})} = \frac{2}{3} + (- \frac{1}{4}) \times \frac{- 4}{7}$
(d) $- \frac{1}{4} \times {\frac{2}{3} + (\frac{- 4}{7})} = {\frac{2}{3} + (\frac{- 4}{7})} - \frac{1}{4}$

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734=7+(△+△+△). Here, △ stands for:

The correct option is C 14⇒314=7+(3△)⇒314−7=3△ ⇒31−284=3△⇒3△=34△=34×13=14[△=14]

$7 \frac{3}{4} = 7 + (△ + △ + △)$ . Here, $△$ stands for:

The correct option is C $\frac{1}{4}$
$\Rightarrow \frac{31}{4} = 7 + (3 △)$
$\Rightarrow \frac{31}{4} - 7 = 3 △$ $\Rightarrow \frac{31 - 28}{4} = 3 △$
$\Rightarrow 3 △= \frac{3}{4}$
$△= \frac{3}{4} \times \frac{1}{3} = \frac{1}{4}$
$[△= \frac{1}{4}]$