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Question

7.Find the value of a, b, c and d from the equation:2a-b 3c+d0 13

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Solution

The given equation is,

[ ab 2a+c 2ab 3c+d ]=[ 1 5 0 13 ]

Since the given matrices are equal, their corresponding elements will be also equal.

ab=1 (1)

2a+c=5 (2)

2ab=0 (3)

3c+d=13 (4)

Solve equation (3), we get:

2ab=0 b=2a (5)

By substituting b=2a in equation (1), we get:

ab=1 a2a=1 a=1

By substituting the value of a in equation (5), we get:

b=2a =2×1 =2

By substituting the value of a in equation (2), we get:

2a+c=5 2×1+c=5 c=52 =3

By substituting the value of c in equation (4), we get:

3c+d=13 3×3+d=13 d=139 =4

Thus, the required values are a=1 , b=2 , c=3 and d=4 .


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