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Question
712−[214+{114−12(32−13−16)}]
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Solution
=712−[214+{ 114−12(32−13−16)}]By simplifying mixed fractions =152−[94+{ 54−12(32−13−16)}]According to BODMAS=152−[94+{ 54−12(3(3)−1(2)−16)}]
=152−[94+{ 54−12(9−2−16)}]
=152−[94+{ 54−12(66)}]
=152−[94+{ 54−12(1)}]
=152−[94+{ 54−12}]
=152−[94+{ 5(1)−1(2)4}]
=152−[94+{ 34}]
=152−[94+ 34]
=152−[124]
=152−[62]
=152−62
=15−62
=92
=412
By simplifying mixed fractions
=152−[94+{ 54−12(32−13−16)}]
According to BODMAS
=152−[94+{ 54−12(3(3)−1(2)−16)}]
=152−[94+{ 54−12(9−2−16)}]
=152−[94+{ 54−12(66)}]
=152−[94+{ 54−12(1)}]
=152−[94+{ 54−12}]
=152−[94+{ 5(1)−1(2)4}]
=152−[94+{ 34}]
=152−[94+ 34]
=152−[124]
=152−[62]
=152−62
=15−62
=92
=412
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