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Standard VIII

Mathematics

Solving Equations Algebraically

7 is added to...

Question

7 is added to a certain number; the sum is multiplied by 5, the product is divided by 9 and 3 is subtracted from the quotient. The remainder left is 12. The number is

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Solution

The correct option is A 20
Let the certain number be $x$

Step I $(x + 7)$

Step II $5 (x + 7)$

Step III $\frac{5 (x + 7)}{9}$

Step IV $\frac{5 (x + 7)}{9} - 3 = 12$

$5 (x + 7) - 27 = 9 \times 12$

$5 x + 35 - 27 = 108$

$5 x = 108 - 8$

$x = \frac{100}{5} = 20$

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7 is added to a certain number; the sum is multiplied by 5, the product is divided by 9 and 3 is subtracted from the quotient. The remainder left is 12. The number is

The correct option is A 20Let the certain number be x Step I (x+7)Step II 5(x+7)Step III 5(x+7)9Step IV 5(x+7)9−3=125(x+7)−27=9×125x+35−27=1085x=108−8x=1005=20

The correct option is A 20
Let the certain number be $x$

Step I $(x + 7)$

Step II $5 (x + 7)$

Step III $\frac{5 (x + 7)}{9}$

Step IV $\frac{5 (x + 7)}{9} - 3 = 12$

$5 (x + 7) - 27 = 9 \times 12$

$5 x + 35 - 27 = 108$

$5 x = 108 - 8$

$x = \frac{100}{5} = 20$