Question

$7log\left(\frac{16}{15}\right)+5log\left(\frac{25}{24}\right)+3log\left(\frac{81}{80}\right)$ is equal to -

• A. 1
• B. log 2
• C. log 3

Answer 1

The correct option is B log 2

$7log\left(\frac{16}{15}\right)+5log\left(\frac{25}{24}\right)+3log\left(\frac{81}{80}\right)$
$=log(\frac{{16}^7}{{15}^7}.\frac{{25}^5}{{24}^5}.\frac{{81}^3}{{80}^3})$
$=log2$