7 luggage of mass 10 kg each, fall on a horizontal conveyor belt in an airport moving at 2 m/s in every 5 seconds. Power of motor operating the belt is __.

56 watt

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70 watt

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112 watt

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140 watt

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Solution

The correct option is A
56 watt
Power = Force $\times$ Velocity
Change in momentum in 5 seconds is $Δ$ P.
Force, F = $\frac{Δ P}{Δ t}$ = $\frac{7 \times 10 \times 2}{5}$
P = $\frac{7 \times 10 \times 2 \times 2}{5}$ = 56 watt

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g = 10 m s^{- 2}

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