7n−3n is always divisible by
4
Substituting n=1, we get
71−31=4
Let P(n):7n−3n is divisible by 4
P(1) is true
Assume P(k) is true
7k−3k is divisible by 47k−3k=4mNow, 7k+1−3k+1=7.(7k−3k)+4.3k=4.(7m+3k)→divisible by 4
P(k+1) is true
Hence, P(n) is true.