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Byju's Answer
Standard XII
Chemistry
First Order Reaction
7.The inversi...
Question
7.The inversion of cane sugar represented by C12H22O11 + H2O ----> C6H12O6 + C6H12O6 is a _______ reaction
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Q.
Assertion :The reaction
C
12
H
22
O
11
C
a
n
e
s
u
g
a
r
+
H
2
O
H
+
−
−
→
C
6
H
12
O
6
G
l
u
c
o
s
e
+
C
6
H
12
O
6
F
r
u
c
t
o
s
e
is a first order reaction. Reason: Change in concentration of
H
2
O
is negligible.
Q.
Cane sugar underoges the inversion as follow:
C
12
H
22
O
11
+
H
2
O
→
C
6
H
12
O
6
+
C
6
H
12
O
6
If solution of 0.025 moles of sugar in 200 gm of water show depression in freezing point 0.372
o
C, then
what % sucrose has inverted.
(
K
f
(
H
2
O
)
=
1.86
K
k
g
m
o
l
1
)
Q.
C
12
H
22
O
11
+
H
2
O
→
C
6
H
12
O
6
+
C
6
H
12
O
6
(excess) (gulcose) (fructose)
Rate law of above equation is expressed as:
Q.
In the below reactions, enzyme A and enzyme B respectively are:
C
12
H
22
O
11
Sucrose
+
H
2
O
Enzyme A
−
−−−−−
→
C
6
H
12
O
6
Glucose
+
2
C
6
H
12
O
6
Fructose
C
6
H
12
O
6
Glucose
Enzyme B
−
−−−−−
→
2
C
2
H
5
O
H
+
2
C
O
2
Q.
Inversion of sucrose
(
C
12
H
22
O
11
)
is a first order reaction and is studied by measuring angle of rotation at different intervals of time
C
12
H
22
O
11
d-Sucrose
+
H
2
O
H
+
−
−
→
C
6
H
12
O
6
d -Glucose
+
C
6
H
12
O
6
l -Fructose
r
0
= angle of rotation at the start,
r
t
= angle of rotation at time ti, and
r
∞
= angle of rotation at the complete reaction, if 50% of sucrose undergoes inversion, then
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