7. The volume of an air bubble is doubled as it rises o from the bottom of lake to its surface. The atmospheric pressure is 75 cm of mercury. The ratio of density of mercury to that of lake water is40/3. The depth of the lake in metre is (1) 10 (2) 15 (3) 20 (4) 2

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Q. The volume of an air bubble is doubled as it rises from the bottom of a lake to its surface. If the atmospheric pressure is

H m

of mercury & the density of mercury is

n

times that of lake water. The depth of the lake is given as

x n H

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x

The volume of an air bubble becomes three times as it rises from the bottom of a lake to its surface. Assuming atmospheric pressure to be 75 cm of Hg and the density of water to be 1/10 of the density of mercury, the depth of the lake is

Q. The volume of an air bubble becomes three times as it rises from the bottom of a lake to its surface. Assuming atmospheric pressure to be 75 cm of Hg and the density of water to be 1/10 of the density of mercury, the depth of the lake.

Q. The temperature of an air bubble while rising from bottom to surface of a lake remains constant but its diameter is doubled. If the pressure on the surface is equal to h meter of mercury column and relative density of mercury is

ρ

, then the depth of the lake in meter, is

Q. In rising from the bottom of a lake to the top, the temperature of air bubble remains unchanged, but the diameter gets doubled. If

h

is the barometric height (expressed in metres of mercury of relative density

ρ

) at surface of the lake, the depth of the lake (in metres) is

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