7 \times 8 - 8 \times 4

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Solution

The correct option is A 24
B Brackets

O Of

D Division

M Multiplication

A Addition

S Subtraction

7 times 8 - 8 times 4

According to BODMAS, Multiplication operation has to be done before Subtraction.

Hence, $7 \times 8 - 8 \times 4 = 56 - 32 = 24$ .

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Similar questions

Q. Why this series occurs in square numbers.

0 \times 0 = 0, 1 \times 1 = 1 d i f f e r e n c e = 1 1 \times 1 = 1, 2 \times 2 = 4 d i f f e r e n c e = 3 2 \times 2 = 4, 3 \times 3 = 9 d i f f e r e n c e = 5 3 \times 3 = 9, 4 \times 4 = 16 d i f f e r e n c e = 7 4 \times 4 = 16, 5 \times 5 = 25 d i f f e r e n c e = 9 5 \times 5 = 25, 6 \times 6 = 36 d i f f e r e n c e = 11 6 \times 6 = 36, 7 \times 7 = 49 d i f f e r e n c e = 13 7 \times 7 = 49, 8 \times 8 = 64 d i f f e r e n c e = 15

8 \times (3 + 2 \times 2) = ?

7 + 7 + 7 + 7 + 8 + 8 + 8 = 7 \times 4 + 8 \times 2

Find the value.

$7 \times 8 - 8 \times 4$ = ?

$Name the multiplication property of rational numbers shown below: (i) \frac{3}{5} \times \frac{- 8}{9} = \frac{- 8}{9} \times \frac{3}{5} (i i) \frac{- 3}{4} \times (\frac{5}{7} \times \frac{- 8}{15}) = (\frac{- 3}{5} \times \frac{5}{7}) \times \frac{- 8}{15} (i i i) \frac{4}{5} \times (\frac{3}{- 8} + \frac{- 4}{7}) = \frac{4}{5} \times \frac{3}{- 8} + \frac{4}{5} \times \frac{- 4}{7} (i v) \frac{- 7}{5} \times \frac{5}{- 7} = 1 (v) \frac{8}{- 9} \times 1 = 1 \times \frac{8}{- 9} = \frac{8}{- 9} (v i) \frac{- 3}{4} \times 0 = 0$

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7 \times 8 - 8 \times 4

The correct option is A 24B Brackets O Of D Division M Multiplication A Addition S Subtraction 7 times 8 - 8 times 4 According to BODMAS, Multiplication operation has to be done before Subtraction. Hence, 7×8−8×4=56−32=24.

The correct option is A 24
B Brackets

O Of

D Division

M Multiplication

A Addition

S Subtraction

7 times 8 - 8 times 4

According to BODMAS, Multiplication operation has to be done before Subtraction.

Hence, $7 \times 8 - 8 \times 4 = 56 - 32 = 24$ .