7x - 1 - 7x - 1 - 507-

7 ^ x 1 ( 1+ 7 ^ 2 ) = 50 / 7 ⇒ 7 ^ x 1 ( 1+49 ) = 50 / 7 ⇒ 7 ^ x 1 ( 50 ) = 50 / 7 ⇒ 7 ^ x 1 = 7 ^ 1 ⇒ x 1= 1 ⇒ x=0 ...

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Sum of Binomial Coefficients of Even Numbered Terms

7x - 1 + 7x +...

Question

$7^{x - 1} + 7^{x + 1} = \frac{50}{7}$ .

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Solution

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7^{x - 1} + 7^{x + 1} = \frac{50}{7}

x

Solve the following equations.
$7^{x + 2} - \frac{1}{7} \cdot 7^{x + 1} - {14.7}^{x - 1} + {2.7}^{x} = 48$

Question 177(i)

Find x.
$- {(\frac{1}{7})}^{- 5} \div - {(\frac{1}{7})}^{- 7} = (- 7)^{x}$

Factorise:

$x^{2} + \frac{1}{4 x^{2}} + 1 - 7 x - \frac{7}{2 x}$

Question 177(i)

Find x.
$- {(\frac{1}{7})}^{- 5} \div - {(\frac{1}{7})}^{- 7} = (- 7)^{x}$

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