$7 x^{2} + x^{3} + x = ?$
$If x = 2$

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Solution

Let us substitute $x = 2$ in the given polynomial $7 x^{2} + x^{3} + x$ as shown below:

$7 x^{2} + x^{3} + x = 7 (2)^{2} + (2)^{3} + 2 = (7 \times 4) + 8 + 2 = 28 + 8 + 2 = 38$

Hence, $7 x^{2} + x^{3} + x = 38$ if $x = 2$ .

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x = 0

x^{3} + 7 x^{2} + x =

x = 7

I f x = 1 - \sqrt{2}

F i n d : {(x - \frac{1}{x})}^{3}

x^{3} - 7 x^{2} - x + 6

(x + 2)

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