Question

7(y+3)-2(x+2)=14

4(y-2)+3(x-3)=2

Solve the system of equation

Answer 1

Solve for x and y : 7(y+3)-2(x+2) =14, 4(y-2) +3(x-3) =2

p7(y+3)-2(x+2)=14

=>7y+21-2x-4=14

=>7y+17-2x=14

=>7y-2x=14-17

=>7y-2x=-3------1st equation

4(y-2)+3(x-3)=2

=>4y-8+3x-9=2

=>4y+3x-17=2

=>4y+3x=2+17

=>4y+3x=19------2nd equation

3[7y-2x=-3]

2[4y+3x=19]

21y-6x=-9-------3rd equation

8y+6x=38-------4th equation

by elimination

adding eqation 3 and 4

we get 29y=29

=>y=1

put 'y' is equal to 1 in equation 3

7-2x=-3

-2x=-10

=>x=5

therefore

y=1,x=5