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Standard IX
Physics
Second Law of Motion
70.A stone is...
Question
70.A stone is projected vertically up from ground with a velocity 40 m/s. The interval of time between the two instants at which the stone is at height of 60 m above the ground is (g=10 m/s²)
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Q.
A stone is projected vertically up from the ground with velocity
40
m
s
−
1
. The interval of time between the two instants at which the stone is at a height of
60
m above the ground is:
[
g
=
10
m
s
−
2
]
Q.
A stone is allowed to fall from the top of a tower
100
m
high and at the same time, another stone is projected vertically upwards from the ground with a velocity of
25
m/s
. The two stones will meet at a height
Q.
A stone A is dropped from a height h above the ground. A second stone B is simultaneously thrown vertically up from a point on the ground with velocity v. The line of motion of both the stones is same. The value of v which would enable the stone B to meet the stone A midway ( at midpoint) between their initial position is:
Q.
A stone is allowed to fall from the top of a tower
100
m
high and at the same time, another stone is projected vertically upwards from the ground with a velocity of
25
ms
−
1
. The two stones will meet after
Q.
A stone is allowed to fall from the top of a tower 100 m high. At the same time, another stone is projected vertically upwards from the ground with a velocity of 25 m/s. Calculate when and where the two stones will meet?
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