Given :
T1=40oC
T2=45oC
n=2
∴ ΔT=T2−T1=45−40=5
Heat supplied at constant pressure
Qp=nCpΔT
∴ 70=2×Cp×5
⟹Cp=7 cal/mol−K
Using Cp−Cv=nR
where R=2 cal/mol−K
⟹ 7−Cv=2×2
Thus Cv=3 cal/mol−K
Heat supplied at constant volume
Qv=nCvΔT
⟹Qv=2×3×5=30 cal
Hence, the amount of heat required to raise the temperature of the same gas through the same range at constant volume is 30 cal