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Byju's Answer
Standard XII
Chemistry
Anomalous Behavior of Lithium Halogens
71 g chlorine...
Question
71
g
chlorine combines with certain weight of a metal giving
111
g
of its chloride metal is
A
40
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B
20
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C
80
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D
None
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Solution
The correct option is
A
40
Let metal be
′
x
′
and there molecular mass be
′
y
′
.
1
C
l
2
+
′
x
′
=
n
x
C
l
2
n
=
no. of mole
[
1
m
o
l
e
=
71
g
m
]
[
1
c
h
l
o
r
i
n
e
a
t
o
m
=
35.5
g
m
]
See that as it replace
2
g
H
=
replacing
2
moles of
H
or
2
+
charge.
thus metal has
2
+
charge
∴
type of metal chloride salt is
x
C
l
2
∴
We know that
C
l
2
+
y
=
x
C
l
2
y
=
molecular mass for
1
m
o
l
e
71
+
y
=
111
y
=
111
−
71
y
=
40
∴
Chloride metal is
40
g
m
.
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Q.
One mole of chlorine combines with certain weight of a metal giving 111g of its chloride. The same amount of metal can displace 2g hydrogen from an acid. The atomic weight of the metal is:
Q.
One mole of chlorine combines with certain weight of metal giving 111 g of its chloride (formula :
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Q.
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