72512 is divisible by 11.
True
Find the sum of the digits in the even places of the given number and the sum of the digits in its odd places. If the differences between the two sums is 0 or a multiple of 11, then the given number is divisible by 11.
example: consider the number 72512.
The sum of its digits at even places = 2 + 1 = 3 and the sum of its digits at odd places = 7 + 5 + 2 = 14.
The difference between the two sums = 14 - 3 = 11; which is a multiple of 11
∴ 72512 is divisible by 11.