Question

73 bags of cement weight 4106.25 kg . find the weight oh 100 such bags?

Answer 1

$$\begin{gathered} \mathrm{Weight}\mathrm{of}73\mathrm{bags}\mathrm{of}\mathrm{cement}=4106.25\mathrm{kg} \\ \mathrm{Weight}\mathrm{of}1\mathrm{bag}\mathrm{of}\mathrm{cement}=\frac{4106.25}{73}=56.25\mathrm{kg} \\ \mathrm{Weight}\mathrm{of}100\mathrm{bags}\mathrm{of}\mathrm{cement}=56.25\times 100=5625\mathrm{kg} \end{gathered}$$