75 atoms of radio active series are decayed in $2$ half lives $(t_{1 / 2} = 1 h r)$ if 100 atoms are taken initially. Number of atoms decayed if $200$ atoms are taken in two hours are:

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150

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200

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Solution

The correct option is A 75
$k = \frac{0.693}{t_{\frac{1}{2}}} \to$ constant

Thus the number of atoms decayed by $t_{\frac{1}{2}}$ will not change based on the number.

Thus the number of decayed atoms is still 75.

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75 atoms of radio active series are decayed in 2 half lives (t1/2=1 hr) if 100 atoms are taken initially. Number of atoms decayed if 200 atoms are taken in two hours are:

The correct option is A 75k=0.693t12→constantThus the number of atoms decayed by t12 will not change based on the number.Thus the number of decayed atoms is still 75.

75 atoms of radio active series are decayed in $2$ half lives $(t_{1 / 2} = 1 h r)$ if 100 atoms are taken initially. Number of atoms decayed if $200$ atoms are taken in two hours are:

The correct option is A 75
$k = \frac{0.693}{t_{\frac{1}{2}}} \to$ constant

Thus the number of atoms decayed by $t_{\frac{1}{2}}$ will not change based on the number.

Thus the number of decayed atoms is still 75.