Question

$75$ mL of $H_{2}S{O}_4$ solution (specific gravity $=1.18$) containing $49$% $H_{2}S{O}_4$ ($w/w$) is diluted to $590$ mL. Calculate molarity of the diluted solution.

• A. $0.7$ M
• B. $7.5$ M
• C. $0.75$ M
• D. $0.25$ M

Answer 1

The correct option is C $0.75$ M

We know, $M_1{V}_1=M_2{V}_2$
$\frac{49}{98}\times 1.18\times 10\times 75=M_2\times 590$
$\therefore M_2=0.75$
Therefore, the molarity of the solution is $0.75$ M.