$75 %$ of a first order reaction was completed in $32 m i n u t e s .$ When was $50 %$ of the reaction will be completed?

24 m i n u t e s

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8 m i n u t e s

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16 m i n u t e s

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4 m i n u t e s

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Solution

The correct option is D $16 m i n u t e s$
$75 %$ completion time $= 2 t_{1 / 2} = 32$ min

So, $t_{1 / 2} = 16$ min

Reaction will complete $50 %$ in $16$ min only.

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75

32

50

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%

99 %

32 m i n .

99.9 %

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