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Substitution

76.a+1/b=b+1/...

Question

76.a+1/b=b+1/c=c+1/a where a is not equal to b not equal to c not equal to 0 find the value of a square + b square +c sqaure

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Solution

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Similar questions

If 1/a + 1/b + 1/c = 1/(a+b+c), where a+b+c and a*b*c is not equal to zero then what's the value of

(a+b)(b+c)(c+a)

□

△

-

B

□

D

D

△

C

C

□

A

B + A

ω

1

∣ ∣ a + b ω + c ω^{2} ∣ ∣

a, b, c

ω

| a + b ω + c ω^{2} |

ϵ

1

∣ a + b w + c w^{2} ∣

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