Question

$76$ grams of fluorine gas contains:

• A. $4$ gram atoms of fluorine atoms
• B. $2$ moles of fluorine molecules
• C. $12\times {10}^{23}$ fluorine molecules
• D. all the above

Answer 1

The correct option is D all the above

The atomic weight of fluorine is 19 g per mole and the molecular weight of fluorine is 38g per mole . Thus, 76 gram fluorine contains $\frac{76}{19}=4$ gram atom .

They also contain $\frac{76}{38}=2$ moles of fluorine molecules.

Thus, the number of molecules present in 76 gram of fluorine $\frac{76}{38}\times 6\times {10}^{23}=12\times {10}^{23}.$