CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Common Rays in Thin Lenses

76. In the di...

Question

76. In the displacement method using a convex lens we obtained two images corresponding to a seperation d of the lens . One image is magnified as much as the other is diminished . If m is the magnification of one image ,find focal length of lens

Open in App

Solution

Suggest Corrections

thumbs-up

0

Similar questions

Q. When the distance between the object and the screen than 4f,we van obtain he image of the object on the screen or the position of a convex lens of focal length f.It is called displacement method .In one case the image is magnified if

I_{2} a n d I_{2}

be the sizes of the two images.then the size of the object is:

x_{1}

be the size of the magnified image and

x_{2}

the size of the diminished image in Lens Displacement Method, then the size of the object is

Q. A convex lens forms a real image with magnification

m_{1}

on a screen.Now,the screen is moved by a distance x and the object is also moved so as to obtain a real image with magnification

m_{2} (> m_{1})

on the screen.Then,the focal length of the lens is

Q. Find the distance of an object from a convex lens if image is two times magnified. Focal length of the lens is

10 cm

Q. A student performs an experiment to estimate the focal length of a convex lens by obtaining the image of a distant window on a white screen. The image formed on the white screen is :
(1) virtual, erect and magnified
(2) real, erect and magnified
(3) real, inverted and diminished
(4) virtual, inverted and diminished

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Thin Lenses: Extended Objects

PHYSICS

Watch in App

explore_more_icon

Explore more

Common Rays in Thin Lenses

Standard XII Physics

Join BYJU'S Learning Program

CrossIcon