Question

$7928$ is not a perfect square. Give reason.

• A. Because last two digits are $28$
  
• B. Because last digit of a number is $8$
  
• C. Because first two digits are not divisible by $8$
• D. Data insufficient
  

Answer 1

The correct option is B Because last digit of a number is $8$

We know that numbers ending with $2,3,7$ and $8$ are not perfect squares.

So, the number $7928$ is not a perfect square because it ends with $8$.