7ax2 +bx+c
Consider the function,
f ( x ) = 1 ( a x 2 + b x + c )
The quotient rule of derivative to find the derivative of the function is,
d d x ( U V ) = ( U V ′ − V U ′ ) V 2
Where U ′ and V ′ are the derivative of their respective functions.
Apply quotient rule of derivative in the given function,
f ′ ( x ) = ( a x 2 + b x + c ) d d x ( 1 ) − 1 d d x ( a x 2 + b x + c ) ( a x 2 + b x + c ) 2 = ( a x 2 + b x + c ) 0 − a d d x x 2 − b d d x x − d d x c ( a x 2 + b x + c ) 2 = 0 − 2 a x − b ( a x 2 + b x + c ) 2 = − ( 2 a x + b ) ( a x 2 + b x + c )
Thus, the derivative of 1 ( a x 2 + b x + c ) is − ( 2 a x + b ) ( a x 2 + b x + c ) .
Consider the function,
The quotient rule of derivative to find the derivative of the function is,
Where
Apply quotient rule of derivative in the given function,
Thus, the derivative of
