Question

$7log\left(\frac{16}{15}\right)+5log\left(\frac{25}{24}\right)+3log\left(\frac{81}{80}\right)$ is equal to

• A. \N
• B. 1
• C. log 2
• D. log 3

Answer 1

The correct option is C log 2

Given expression
$=7log\left[\frac{2^4}{3\times 5}\right]+5log\left[\frac{5^2}{3\times 2^3}\right]+3log\left[\frac{3^4}{5\times 2^4}\right]$
$=7[4log2-log3-log5]+5[2log5-log3-3log2]+3[4log3-log5-4log2]$
$=log2$