Question

${}_7{M}^{14}+{}_{2}H{e}^4\to X+{}_1{H}^1,X$ is:

• A. ${}_8{O}^{18}$
• B. ${}_8{O}^{17}$
• C. ${}_8{N}^{14}$
• D. ${}_7{N}^{15}$

Answer 1

Answer: (B)

${}_8{O}^{17}$

${}_7{M}^{14}+{}_{2}H{e}^4\to {}_8{O}^{17}{+}_1{H}^1$

Balancing mass number: $14+4=17+1=18$

Balancing atomic number: $7+2=8+1=9$