$(7 x^{2} - 2 y^{2} - 6 x y + y) - (2 y^{2} + 2 x^{2} - 1 + 2 x y)$

Open in App

Solution

$(7 x^{2} - 2 y^{2} - 6 x y + y) - (2 y^{2} + 2 x^{2} - 1 + 2 x y)$
$= 7 x^{2} - 2 x^{2} - 2 y^{2} - 2 y^{2} - 6 x y - 2 x y + y + 1$
$= 5 x^{2} - 4 y^{2} - 8 x y + y + 1$ .

Suggest Corrections

Similar questions

({7 x}^{2} - 2 x y - {6 y}^{2}) + ({9 y}^{2} + 12 x y - {12 x}^{2}) - (8 x y + {2 y}^{2} - {3 x}^{2})

3 x^{2} + 3 y^{2} + 2 x y = 2

45^{\circ}

x

y

What should be subtracted from 2 x^{2} - 4 y^{2} + 6 x y + 10 to obtain - 2 x^{2} - 3 y^{2} + 6 x y + 10 ?

X_{2} + Y_{2} ⇌

X Y ⇌ \frac{1}{2} X_{2} + \frac{1}{2} Y_{2}

Join BYJU'S Learning Program