7x + 6y + 4z = 122
4x + 5y + 3z = 88
9x + 2y + z = 78

x < y = z

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\leq

y < z

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x < y > z

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x = y > z

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x = y = z or relation cannot be established

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Solution

The correct option is A x < y = z
7x + 6y + 4z = 122 - - (1)
4x + 5y + 3z = 88 - - (2)
9x + 2y + z = 78 - -(3)
From (1) and (2) $\Rightarrow$ 5x - 2y = 4 - (a)
From (2) and (3) $\Rightarrow$ 23x + y = 146 - (b)
From (a) and (b) $\Rightarrow$ x = 6, y = 8. Put values in eqn (3) $\Rightarrow$ z = 8

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Similar questions

7 x + 6 y + 4 z = 122

4 x + 5 y + 3 z = 88

9 x + 2 y + z = 78

x + 5 y + 4 z = 3

2 x + 2 y + 3 z = 4

4 x - 2 y + z = 9

x, y, z

6 x + 5 y + λ z = 0

3 x - y + 4 z = 0

x + 2 y - 3 z = 0

5 x - 4 y - {7 x - (3 z - 2 y) + 4 z - 3 (x + 3 y - 2 z)}] =

x + 2 y + 3 z = 9; 2 x + 3 y + z = 4; 4 x + 5 y + 4 z = 15

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