7x×(−5yz)×2xz =
−70x2yz2
When we multiply monomials, we first multiply the coefficients and then multiply the variables by adding the exponents. This will always give a monomial.
On multiplying x with x, its power is raised to 2; on multiplying z with z its power is also raised to 2. Also, multiplying all the coefficients, we get −70.
Therefore the answer is −70x2yz2.