$7 x y$ is one of the factors of $14 x^{2} y^{2} + 56 x y + 105 x^{3} y^{3}$ .

True

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False

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Solution

The correct option is A True

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Similar questions

7 x y

14 x^{2} y^{2} + 56 x y + 105 x^{3} y^{3}

7 x y, 35 x^{2} y^{3}

z + 7 + 7 x y + x y z

Factorise: (x⁴- 14x²y² - 51y⁴).

7 x y, 35 x^{2} y^{3}

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