Given complex number is, ( 1 #x2212;i ) 4 On simplifying the given expression, we get ( 1 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Mathematics

Properties of Iota

8. 1-1 4

Question

8. (1-1)4

Open in App

Solution

Given complex number is,

( 1−i ) 4

On simplifying the given expression, we get

( 1−i ) 4 = [ ( 1−i ) 2 ] 2 = [ 1+ i 2 −2i ] 2 = [ 1−1−2i ] 2 = [ −2i ] 2

Simplify further.

( 1−i ) 4 =4 i 2 =−4

Thus, the given expression in the form of a+ib is ( −4 )+i⋅0.

Suggest Corrections

Similar questions

What is the value of a if 6(2a - 1) + 8 = 14?

Find the product:
$\frac{14}{8} \times \frac{1}{4}$

Q. The ages of students of 10^th class, in a school are as follows. The ages are given in years months.

14

-

6, 13

-

11, 15

-

2, 16

-

0, 13

-

9, 14

-

5, 14

-

7, 14

-

0,
15

-

0, 15

-

1, 16

-

2, 14

-

1, 13

-

11, 16

-

0, 14

-

5, 14

-

0,
14

-

8, 14

-

4, 15

-

4, 15

-

9, 15

-

1, 14

-

10, 14

-

-

8

15

-

1, 14

-

1, 16

-

0, 13

-

10, 14

-

0, 15

-

0, 13

-

6, 13

-

11,
14

-

3, 14

-

8, 14

-

7, 14

-

8, 14

-

1, 15

-

0, 15

-

1, 14

-

4,
14

-

9, 14

-

9, 14

-

10, 15

-

3, 14

-

9, 13

-

10, 13

-

2, 15

-

1,

Prepare a grouped frequency distribution table (classes; 13

-

14, 14

-

15, 15

-

16, ....)

What is the mass ratio of nitrogen to hydrogen in an NH₃ molecule?

\frac{7}{8} \times (\begin{matrix} \frac{17}{13} + \frac{14}{13} \end{matrix}) = (\begin{matrix} \frac{7}{8} \times \frac{14}{13} \end{matrix}) + (\begin{matrix} \frac{7}{8} \times \frac{17}{13} \end{matrix})

If true then enter

1

and if false then enter

0

Join BYJU'S Learning Program

8. (1-1)4

Given complex number is, ( 1−i ) 4 On simplifying the given expression, we get ( 1−i ) 4 = [ ( 1−i ) 2 ] 2 = [ 1+ i 2 −2i ] 2 = [ 1−1−2i ] 2 = [ −2i ] 2 Simplify further. ( 1−i ) 4 =4 i 2 =−4 Thus, the given expression in the form of a+ib is ( −4 )+i⋅0.

Given complex number is,

( 1−i ) 4

On simplifying the given expression, we get

( 1−i ) 4 = [ ( 1−i ) 2 ] 2 = [ 1+ i 2 −2i ] 2 = [ 1−1−2i ] 2 = [ −2i ] 2

Simplify further.

( 1−i ) 4 =4 i 2 =−4

Thus, the given expression in the form of a+ib is ( −4 )+i⋅0.