81-3- 40-6- 160-2-2 -

The correct option is C 5.9Here, 2^3 × 1.3× (2^2)^× 0.6× 2^4 × 0.2 = 2? ⇒ 2^3.9 + 1.2 + 0.8 = 2^? [∵ m^x × m^y × m^z = m^x + y + z] ⇒ 2^5. ...

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Quantitative Aptitude

Series

81.3× 40.6× 1...

Question

$8^{1.3} \times 4^{0.6} \times 16^{0.2} = 2^{?}$

2.1

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5.9

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4.7

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Solution

The correct option is C 5.9
$H e r e, 2^{3 \times 1.3} \times (2^{2})^{\times 0.6} \times 2^{4 \times 0.2} = 2 ? \Rightarrow 2^{3.9 + 1.2 + 0.8} = 2^{?}$
$[∵ m^{x} \times m^{y} \times m^{z} = m^{x + y + z}]$
$\Rightarrow 2^{5.9} = 2^{?} \Rightarrow ? = 5.9$

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81.3×40.6×160.2=2?

The correct option is C 5.9Here,23×1.3×(22)×0.6×24×0.2=2?⇒23.9+1.2+0.8=2? [∵mx×my×mz=mx+y+z] ⇒25.9=2?⇒?=5.9

$8^{1.3} \times 4^{0.6} \times 16^{0.2} = 2^{?}$

The correct option is C 5.9
$H e r e, 2^{3 \times 1.3} \times (2^{2})^{\times 0.6} \times 2^{4 \times 0.2} = 2 ? \Rightarrow 2^{3.9 + 1.2 + 0.8} = 2^{?}$
$[∵ m^{x} \times m^{y} \times m^{z} = m^{x + y + z}]$
$\Rightarrow 2^{5.9} = 2^{?} \Rightarrow ? = 5.9$