The correct option is A greater than8:2 and 6:2 can be written as 8/2 and nbsp;6/2 respectively. As 8/2 is 4 and nbsp;6/2 is 3. 4 is greater than 3, so 8/ ...

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Standard IX

Mathematics

Comparison of Ratios

8:2 is 6:2

Question

8:2 is 6:2

greater than

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less than

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equal to

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incomparable to

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Solution

The correct option is A greater than
8:2 and 6:2 can be written as $\frac{8}{2}$ and $\frac{6}{2}$ respectively.

As $\frac{8}{2}$ is 4 and $\frac{6}{2}$ is 3.

4 is greater than 3, so $\frac{8}{2}$ is greater than $\frac{6}{2}$ .

Hence, 8:2 is greater than 6:2

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Similar questions

Q. THe value of

\frac{8^{3} + 6^{3}}{8^{2} - 8 \times 6 + 6^{2}}

Q. simplify:

\frac{18 \sqrt{3}}{12 - 6 \sqrt{2}} + \frac{3 \sqrt{2} - 2 \sqrt{3}}{8 - \sqrt{6}} - \frac{12 \sqrt{2} + 4 \sqrt{6}}{8 - \sqrt{12}}

Q. In the given series

5, 6, 8, 2, 5, 5, 2, 5, 4, 2, 8, 5, 3, 5, 2, 8, 6, 8, 2, 5, 2, 8, 6, 2, 8, 5, 7, 2, 8

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' has come before

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but

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Q. In the given series

5, 6, 8, 2, 5, 5, 2, 5, 4, 2, 8, 5, 3, 5, 2, 8, 6, 8, 2, 5, 2, 8, 6, 2, 8, 5, 7, 2, 8

how many times the number

^{'} 2^{'}

has come before

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Q. Simplify

\frac{2 \sqrt{6}}{\sqrt{2} + \sqrt{3}} + \frac{6 \sqrt{2}}{\sqrt{6} + \sqrt{3}} - \frac{8 \sqrt{3}}{\sqrt{6} + \sqrt{2}}

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8:2 is 6:2

The correct option is A greater than8:2 and 6:2 can be written as 82 and 62 respectively. As 82 is 4 and 62 is 3. 4 is greater than 3, so 82 is greater than62. Hence, 8:2 is greater than 6:2

The correct option is A greater than
8:2 and 6:2 can be written as $\frac{8}{2}$ and $\frac{6}{2}$ respectively.

As $\frac{8}{2}$ is 4 and $\frac{6}{2}$ is 3.

4 is greater than 3, so $\frac{8}{2}$ is greater than $\frac{6}{2}$ .

Hence, 8:2 is greater than 6:2