$8.2 L$ of an ideal gas weighs $9.0 g$ at $300 K$ and $1 a t m$ pressure. The molecular mass of gas is :

9

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27

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54

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81

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Solution

The correct option is C $27$
$P V = \frac{W}{M} R T$

$∴$ The molecular mass of gas is $M = \frac{W R T}{P V} = \frac{9.0 \times 0.0821 \times 300 K}{1 \times 8.2} = 27 g / m o l$

Hence, the correct option is $B$

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