Question

$8(2x-5)-6(3x-7)=1$

Answer 1

$8(2x-5)-6(3x-7)=1$( Open the bracket and solve it further )

$8\times 2x-8\times 5-6\times 3x+6\times 7=1$

$16x-40-18x+42=1$

$16x-18x=1-42+42$( Bring constant terms from the left side to the right side and while doing so the sign of the respective terms gets change )

$-2x=-1$( solve the right and left parts separately )

$x=\frac{-1}{-2}$( Bring $-2$from left side to right side and while doing so division gets changed to multiplication and solve further )

$x=\frac{1}{2}$

Hence, the value of $x=\frac{1}{2}$