Question

# $8\left(2x-5\right)-6\left(3x-7\right)=1$

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Solution

## $8\left(2x-5\right)-6\left(3x-7\right)=1$( Open the bracket and solve it further )$8×2x-8×5-6×3x+6×7=1$$16x-40-18x+42=1$$16x-18x=1-42+42$( Bring constant terms from the left side to the right side and while doing so the sign of the respective terms gets change )$-2x=-1$( solve the right and left parts separately )$x=\frac{-1}{-2}$( Bring $-2$from left side to right side and while doing so division gets changed to multiplication and solve further )$x=\frac{1}{2}$Hence, the value of $x=\frac{1}{2}$

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