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Question

8(3a2b)210(3a2b)

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Solution

Let y=8(3a2b)210(3a2b)
taking (3a2b) common we get
y=(3a2b)[8(3a2b)10]
y=(3a2b)[24a16b10]
on solving we get
y=72a248ab30a48ab+32b2+20b
y=72a2+32b296ab30a+20b
y=72a230a+32b2+20b96ab.

1179598_1350656_ans_2ad897a19bf54826b06082cf40cfe747.JPG

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