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Byju's Answer
Standard XII
Mathematics
Bijective Function
83a-2b2-103a-...
Question
8
(
3
a
−
2
b
)
2
−
10
(
3
a
−
2
b
)
Open in App
Solution
Let
y
=
8
(
3
a
−
2
b
)
2
−
10
(
3
a
−
2
b
)
taking
(
3
a
−
2
b
)
common we get
y
=
(
3
a
−
2
b
)
[
8
(
3
a
−
2
b
)
−
10
]
y
=
(
3
a
−
2
b
)
[
24
a
−
16
b
−
10
]
on solving we get
y
=
72
a
2
−
48
a
b
−
30
a
−
48
a
b
+
32
b
2
+
20
b
y
=
72
a
2
+
32
b
2
−
96
a
b
−
30
a
+
20
b
y
=
72
a
2
−
30
a
+
32
b
2
+
20
b
−
96
a
b
.
Suggest Corrections
4
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