$(- 8) - 7 - (+ 6) - 5 - (- 4) - 3 - 2 - (- 1) + 31$ = ___

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Solution

$(- 8) - 7 - (+ 6) - 5 - (- 4) - 3 - 2 - (- 1) + 31$

$= - 8 - 7 - 6 - 5 + 4 - 3 - 2 + 1 + 31$

$= (31 + 1 + 4) - (8 + 7 + 6 + 5 + 3 + 2)$

$= 36 - 31$

$= 5$

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Similar questions

Q. Find the value of:

(1) 3⁶
(2) 6³
(3) 2⁶
(4) 1⁸
(5) 5⁴
(6) 4³
(7) 10⁵
(8) 10⁷
(9) 7⁴
(10) 8²

Q. What should come next in the following number series?
9 8 7 6 5 4 3 2 1 8 7 6 5 4 3 2 1 7 6 5 4 3 2 1

Find the value of:

(1)

(2)

(3)

(4)

(5)

Re-arrange suitably and find the sum in each of the following :

(i) $\frac{11}{12} + \frac{- 17}{3} + \frac{11}{2} + \frac{- 25}{2}$

(ii) $\frac{- 6}{7} + \frac{- 5}{6} + \frac{- 4}{9} + \frac{- 15}{7}$

(iii) $\frac{3}{5} + \frac{7}{3} + \frac{9}{5} + \frac{- 13}{15} + \frac{- 7}{3}$

(iv) $\frac{4}{13} + \frac{- 5}{8} + \frac{- 8}{13} + \frac{9}{13}$

(v) $\frac{2}{3} + \frac{- 4}{5} + \frac{1}{3} + \frac{2}{5}$

(vi) $\frac{1}{8} + \frac{5}{12} + \frac{2}{7} + \frac{7}{12} + \frac{9}{7} + \frac{- 5}{16}$

Evaluate :

$(i) \frac{3}{7} + \frac{- 4}{9} + \frac{- 11}{7} + \frac{7}{9} (i i) \frac{2}{3} + \frac{- 4}{5} + \frac{1}{3} + \frac{2}{5} (i i i) \frac{4}{7} + 0 + \frac{- 8}{9} + \frac{- 13}{7} + \frac{17}{9} (i v) \frac{3}{8} + \frac{- 5}{12} + \frac{3}{7} + \frac{3}{12} + \frac{- 5}{8} + \frac{- 2}{7}$

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(−8)−7−(+6)−5−(−4)−3−2−(−1)+31 = ___

(−8)−7−(+6)−5−(−4)−3−2−(−1)+31 =−8−7−6−5+4−3−2+1+31 =(31+1+4)−(8+7+6+5+3+2) =36−31 =5

$(- 8) - 7 - (+ 6) - 5 - (- 4) - 3 - 2 - (- 1) + 31$ = ___

$(- 8) - 7 - (+ 6) - 5 - (- 4) - 3 - 2 - (- 1) + 31$

$= - 8 - 7 - 6 - 5 + 4 - 3 - 2 + 1 + 31$

$= (31 + 1 + 4) - (8 + 7 + 6 + 5 + 3 + 2)$

$= 36 - 31$

$= 5$